24=h^2+4h

Solution for 24=h^2+4h equation:

24=h^2+4h

We move all terms to the left:

24-(h^2+4h)=0

We get rid of parentheses

-h^2-4h+24=0

We add all the numbers together, and all the variables

-1h^2-4h+24=0

a = -1; b = -4; c = +24;
Δ = b2-4ac
Δ = -42-4·(-1)·24
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{7}}{2*-1}=\frac{4-4\sqrt{7}}{-2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{7}}{2*-1}=\frac{4+4\sqrt{7}}{-2}
$